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so, (4+6+4+1=)15 equilibria?
That should be correct, assuming all the males are actually identical. If they have different preferences, or if the blonde may select one over another when there's a conflict, then the solutions could change.
Fun fact: The number of Nash equilibria, including randomized ones, which we call "mixed strategies", is always odd.
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Thanks for formalizing it and hinting me in the right direction. And thanks for the sats :)
EDIT: so, (4+6+4+1=)15 equilibria?