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50 sats \ 13 replies \ @Bell_curve 1 Jul \ parent \ on: What's the best of best 'Game Show' of all time? gaming
I agree with your top 3
The Monty Hall problem is a classic. I finally understood the solution 10 years ago
I still don’t get it.
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Monty Hall solution!
I realized I am a terrible remote teacher
The video is 3 minutes
3 doors 🚪, one prize 🏆
I pick door 🚪 2 which has p = 1/3 where p is probability
That means my chance of getting nothing is 2/3
The combined probability of the two doors 🚪 I didn’t select is 2/3
Now Monty Hall opens door 🚪 3 which has no prize ; this means p = 0 for door 🚪 3
That means door 🚪 1 has p = 2/3
The combined probability of door 1 and door 3 is always 2/3
Since p for door 🚪 3 is 0 then p for door 🚪 1 is 2/3
Monty Hall asks me do I want to stay or choose door 🚪 1
I tell Monty Hall I want to switch , give me door 🚪 1
I double my probability by switching
Monty did us a favor by showing us one empty door
Hope this is clear. It’s easier to explain with pen 🖊️ and paper 📝
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Let me start over and be more concise
Imagine there are 100 doors
You pick 1 door
Probability is 1 percent
Monty opens 98 doors with goats
There is a 99 percent chance it’s not the door you selected
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The combined probability of two doors is always 2/3
We start with
1/3 + 1/3 + 1/3 = 1
We eliminate a door
1/3 + 0 + 2/3 = 1
The key is your initial selection probability never changes
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The combined probability of your door and the door already open is 1/3 + 0
The probability of the open door is 0
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If you switch p is 2/3
If you stay p is 1/3
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The probability of each door has to add up to 1 or 3/3
Eliminating one of the goat 🐐 doors doesn’t change the original probabilities
Original probabilities are 1/3 🏆 and 2/3 goat