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The combined probability of your door and the door already open is 1/3 + 0
The probability of the open door is 0
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If you switch p is 2/3
If you stay p is 1/3
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I get what you are saying but still doesn’t seem right.
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The probability of each door has to add up to 1 or 3/3
Eliminating one of the goat 🐐 doors doesn’t change the original probabilities
Original probabilities are 1/3 🏆 and 2/3 goat
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Yes but then the combined probability of my door and the one already opened is also 2/3 so if my door plus opened and the door I didn’t pick plus the opened one both are 2/3 why is it beneficial to switch?