Gravitational potential energy = $U$ = $\frac{GMm}{R}$

Escape velocity = $v_{esc}$ = $\sqrt{\frac{2GM}{r}}$

Kinetic energy of launch:

Kinetic energy after launch = $K_0-U$ = $3U$

So the answer is D) $\sqrt{3}{v}_{esc}$

I didn't remember the escape velocity formula off the top of my head, so the answer is no.

Me plus looking it up would look like what @SimpleStacker did.

I didnt want to get too cute with the answer but there arent a lot of details provided, so I do make some assumptions.

1. There is gravity on the planet (clearly because it has mass and a given escape velocity)
2. There is matter in outer space that will have gravity

The speed exceeds the escape velocity so greatly that I will say that the rock will land inside some mass in outer space after which the speed of the rock will be:

A) Zero

I was way too late to the game. did that ken game ever end?