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0 sats \ 3 replies \ @tomlaies 31 Jan \ on: Call for nodes reconfiguration: minrelaytxfee=0.00000001 bitcoin_Mining
1 sat/vbyte is a clean and round number. What would less than 1 sat even mean? What's when you use an odd number of vbytes? Buy more unused vbytes to fill out a whole sat? or round the fees up/down? ceiling? Is there even pricing pressure here, do miners want to sell block space for less?
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0 sats \ 2 replies \ @gregtonoski OP 31 Jan
Transaction fee is quoted in natural numbers, e.g. 97 sats for a transaction. A fee-rate sat/vbyte is derivative and doesn't exist on the chain. There isn't any rounding problem.
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40 sats \ 1 reply \ @tomlaies 31 Jan
Just because something is derivative doesn't make it not not real.
At some point the price for 97vbytes and for 98vbytes would cost the same price. Alas, this isn't a "problem" per se but what would that look like tho.
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0 sats \ 0 replies \ @nullcount 31 Jan
At some point (a pair of distinct fee rates) the price for N bytes and M bytes can cost the same price.
Example:
Tx_A is 1,000 bytes pays 1sat/byte Tx_B is 500 bytes pays 2sat/byte
Both cost 1,000 sats
I suppose your example for 97/98 bytes would look similar.
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