pull down to refresh

It might help to assemble four quarter circles into a full one:
Let's say the doubly shaded right triangles have shorter sides .
The outer square's side length is , area .
We have to subtract the four white rectangles with area each.
Further add the doubly shaded triangle areas (they count twice).
Then the answer is obviously a fourth of that.
That's how far I got, but I couldn't get and .
I didn't proceed that way, but I imagine this may work too. I'll post the answer tomorrow.
reply