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597 sats \ 1 reply \ @supertestnet 14 Jan \ on: Unbreakable legacy bitcoin
Reviewing your script, I think it has two problems:
(1) it appears like the 3 of 5 option has to wait a year. Based on your description, I don't think that's what you want. You said, "You can spend money at any time with 3 of 5." But the script for the 3 of 5 has a 1 year timelock just like the one for the non-3-of-5.
(2) It appears like the 2-of-5 script and the 1-of-5 script are currently encumbered by an identical timelock. Which means the 1-of-5 person can take the money after waiting only 1 year. Based on your description, I don't think that's what you want. You said, "after another 52596 blocks, the multi-sig reverts to 1 of 5," and I think by "another 52596 blocks" you mean "an additional 52596 blocks."
To fix these issues, you could rewrite the script like this:
   IF
       //this branch requires no timelock at all, so the 3 of 5 can spend at any time
       3 <pubKey1> <pubKey2> <pubKey3> <pubKey4> <pubKey5> 5 OP_CHECKMULTISIG
   ELSE
       //the following branches are encumbered by different timelocks
       IF
           //if you only have 2 keys out of 5, you have to wait 1 year
           //but the 3 of 5 can renew the 1 year wait time by spending the money
           //before the year is up using the branch above this one
           <52596> OP_CHECKSEQUENCEVERIFY OP_DROP
           2 <pubKey1> <pubKey2> <pubKey3> <pubKey4> <pubKey5> 5 OP_CHECKMULTISIG
       ELSE
           //if you only have 1 key out of 5, you have to wait 2 years
           //but the 3 of 5 can renew the 2 year wait time by spending the money
           //before the 2 years are up using the first branch
           //and the 2 of 5 can also renew the 2 year wait time by spending the money
           //before the 2 years are up using the branch above this one
           //though only after themselves waiting at least 1 year 
           <105192> OP_CHECKSEQUENCEVERIFY OP_DROP
           1 <pubKey1> <pubKey2> <pubKey3> <pubKey4> <pubKey5> 5 OP_CHECKMULTISIG
       ENDIF
   ENDIF
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0 sats \ 0 replies \ @DiedOnTitan OP 15 Jan
This is very helpful! I really enjoy these OP code puzzles that solve established use cases. Cheers!
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