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If
a^a = 2^\sqrt{200}
then
a^2 =\ ?
Previous iteration: #823793 (answer in #823807). Solving this problem seems to be a door to a Wall St Job (#823870)~~
2^{\sqrt{200}} = 2^{\sqrt{100}*\sqrt{2}} = 2^{10*\sqrt{2}} = \sqrt{2}^{2*10*\sqrt{2}} = \sqrt{2}^{5*4*\sqrt{2}} = (4*\sqrt{2})^{4*\sqrt{2}} = a^a
Hence, a=4*\sqrt{2} and a^2=32.
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