Evaluate, without using a calculator, which one is bigger: 10^{36} \text{ or } 9^{37}\ ? Sats will be given for each different approach. Previous iteration: #815243 (fun variant in #815534).
(1+x)^r \geq 1+rx
to the inner term10^{36} > 9^{37}
,10^{36} > 9^{36}
.(10/9)^{36}
it will equal the LHS and that multiplier is greater than 9 (I'm pretty sure).