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Evaluate, without using a calculator, which one is bigger:
10^{36} \text{ or } 9^{37}\ ?
Sats will be given for each different approach.
Previous iteration: #815243 (fun variant in #815534).
10^{36} > 9^{37}
10^{36} > 9 * 9^{36}
\frac{10^{36}}{9^{36}}  > 9
(\frac{10}{9})^{36}  > 9
(1 + \frac{1}{9})^{36}  > 9
((1 + \frac{1}{9})^9)^4 > 9
Applying Bernoulli's inequality (1+x)^r \geq 1+rx to the inner term
(1+\frac{1}{9})^9 \geq 1+9*\frac{1}{9}
(1+\frac{1}{9})^9 \geq 2
Inserting into the outer term
2^4 > 9
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I think it's 10^{36} > 9^{37},
Obviously, 10^{36} > 9^{36}.
If you multiply the RHS by (10/9)^{36} it will equal the LHS and that multiplier is greater than 9 (I'm pretty sure).
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.../watch?v=Opp1EDSC-Ho
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Did not use a calculator, but used ChatGPT:
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10^36 is bigger.
My approach is very childish like i imagined having stacks of 10, 36 layer higher. And stack of 9s , 37 layer higher.
I hope I'm not wrong lol
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Take heed, a characteristic single sat zap was just received. @Scroogey's neurons are on the case...
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Wow, 5 different stackers zapped this post within 5 minutes of posting this...
Did I just hit the optimal posting time (9 AM CST)?
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Congrats on the time lottery!
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