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30 sats
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@Filiprogrammer
17 Dec 2024
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on: [Bitcoin Puzzle] Probability of private key collisions, part 1
bitcoin
\frac{2^{75.51747}}{8*10^9} = 6.759797398 * 10^{12} = 2^{42.62012}
So each person would have to generate approximately
2^{42.6}
or 6.7 trillion keys for there to be a 0.1% chance of a Segwit address collision.
So time to switch to taproot? hmm
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100 sats
\frac{2^{75.51747}}{8*10^9} = 6.759797398 * 10^{12} = 2^{42.62012}2^{42.6}or 6.7 trillion keys for there to be a 0.1% chance of a Segwit address collision.