Can you find the radius of the circle inscribed in this Reuleaux triangle?
A Reuleaux triangle comprises three arcs of circles with centers A, B, and C. The radius of each of these circles is equal to 6cm.
Previous iteration: #744872 (brute force answers in #745445 are correct, I'll give the reasoned answer later tonight, hopefully).
Also, check out @0xbitcoiner's problem: #746482
s
of the ABC inscribed triangle is 6cm because of how the Reuleaux triangle is composed. That allows us to get the center positionp
from any vertex, for it's equal to 2/3 of the triangle's heighth
, thus:s = 6 cm
h = sen(60°) \cdot s = { \sqrt{3} \over 2 } \cdot s
p = { 2 \over 3 } h = { \sqrt{3} \over 3 } \cdot s
r
of the inscribed circle is:r = s - p = s - { \sqrt{3} \over 3 } \cdot s = s \cdot \left( 1 - { \sqrt{3} \over 3 } \right)
r = 2 \cdot \left( 3 - { \sqrt{3} } \right) cm = 2.536 cm
3^2 + 5^2 = 6^2
.5 + 1 = 6
.1:2:\sqrt{3}
.\frac{3}{\sqrt{3}}+1 \approx 2.732
.