reply on: [Daily puzzle] Simple algebra problem. \ stacker news ~science

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Not sure how you got to this expression...

\frac{( 27 * 343 ) ^{x}}{( 63 * 147 ) ^{x}} = \frac{37}{21}

(\frac{27 * 343}{63 * 147})^{x} = \frac{37}{21}

1^{x} = \frac{37}{21}

I can't remember how to solve x. (log?)

a^{x} + b^{x} \neq = (ab)^{x}

You can easily check this inequality using $a = 2$ , $b = 3$ and $x = 2$ .

I've been looking at it wrong. Where do you have +, I saw x

a^{x} \times b^{x} = (ab)^{x}

I need to replace the lenses in my glasses

Honest mistake ;)