I've been looking at it wrong. Where do you have +, I saw x

$$
a^x × b^x = (ab)^x
$$

I need to replace the lenses in my glasses



$$
a^x + b^x \neq (ab)^x
$$
You can easily check this inequality using $$a=2$$, $$b=3$$ and $$x=2$$.

south_korea_ln

$$
\frac{(27*343)^x}{(63*147)^x} = \frac{37}{21}
$$

$$
(\frac{27*343}{63*147})^x= \frac{37}{21}
$$

$$
1^x = \frac{37}{21}
$$

I can't remember how to solve x. (log?)


0xbitcoiner

science

[Daily puzzle] Simple algebra problem.

Not sure how you got to this expression...