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My bad - I am not a C programmer. Here is a corrected version that follows the convention of writing proper C:
#include<stdio.h> #include<math.h> double AttackerSuccessProbability(double q, int z) { double p = 1.0 - q; double lambda = z * (q / p); double sum = 1.0; int i, k; for (k = 0; k <= z; k++) { double poisson = exp(-lambda); for (i = 1; i <= k; i++) poisson *= lambda / i; sum -= poisson * (1 - pow(q / p, z - k)); } return sum; } int main() { //If the attacker is one block behind and there is 49% of dishones nodes double prob = AttackerSuccessProbability(0.49, 1); puts("The probability of the success of the attacker when they are 1 block behind the honest 51% majority of nodes:"); printf("%f\n", prob); return 0; }
The first version works just as well, but is not as elegant.