1020 sats \ 1 reply \ @Michelson_Morley 25 Oct 2023 \ parent \ on: Is Quantum Computing really a threat? If that's the case, how? bitcoin
No, I was wrong, specifically about the SHA-256 vulnerability. Thank you for giving me a chance to go on a bitcoin/cryptography rabbit hole journey!
I would still warn about being too confident in network security. I'm currently focusing my studies on this and it really is absurd how insecure everything is. How much does it matter that the bitcoin miner node is safe, if it is easy to gain access to, or easy to intercept its message of a successful block?
HTTP compression endangers the whole world, and not even using quantum computers:
And once quantum computers become operational, (hell, even today, snowden tells us that the NSA has backdoored TLS/HTTPS), what happens when every malicious actor knows the IP address of every mining node? I can tell you one thing that might happen, they might decide to park their car outside the miners house and use electromagnetic detectors (etc) to gain knowledge about the ciphers you communicate by.
If you have make a wireless SSH connection to your server and type a password instead of using public keys, did you know that a sniffer can see every time you pressed a key? Not which key it was, but this info still narrows it down the password brute force absurdly..
That''s the trouble. It's not enough to secure one part, every layer of network protocol as well as everyone (who can dox you)s behavior, and ideally that should be done now. Yesterday even. Every asymmetric public key system, such as digital certifications from LetsEncrypt or one of the other 4 companies (in the world) who provide them, the rely on too few bits even now (this I also learned from Snowden). The NSA can see you.
Going back to bitcoin, its encryption is quantum vulnerable today like TLS before 1.3 (apparenty bitcoin uses elliptic curves somewhere and not just hashing? does anyone care to explain to me?).
And for most networks (and all obscured repeated behavior) can by enough observations eventually give you the compelte unobscured behavior from the moment you begain observing (unless you use forward secrecy, but the point still stands, because again, there are so many layers that need to be unbreakable!). Simply due to Bayes theorem. The first time I programmed one of these (a hidden markov model) was in my final algorithms class, I was blown away that it was even physically possible.
God i love programming. @ekzyis you're a white hat, you know more than me about this. Feel free to weigh in :) (or anyone else).
Thx for the explanation Morley!
reply