Ah right, sure. The likelihood of C-A-A being found before C-B should then just be $$x$$.

Here's a hint: Is the probability of Alice winning the C-A-A vs. C-B race different from the probability of Alice winning the C-A vs. C-B race?

SimpleStacker

That sounds like a big mistake, not a small mistake! :grin:

I agree, and retract my guess. I’m gonna have to wait for someone else to correct me, though.

math

bitcoin

Bitcoin Math Puzzle #002: Selfish Mining Pt. 2

That sounds like a big mistake, not a small mistake! :grin:

I agree, and retract my guess. I’m gonna have to wait for someone else to correct me, though.