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3 sats \ 4 replies \ @jakoyoh629 11 Apr \ parent \ on: Weekend Puzzle: Least Common Multiple of Consecutive Numbers math

number = 1
found = false

while ( not found )
--found = true

--for ( i = 1 until i = 20 )
----if ( number / i diff 0 )
------found = false
------stop

write
compose
3 sats \ 3 replies \ @SimpleStacker OP 11 Apr

I don't think works. as written it will stop on i = 2 with found = false and number = 1

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3 sats \ 2 replies \ @jakoyoh629 11 Apr

The stop only breaks the for loop, the while loop keeps going. No?

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3 sats \ 1 reply \ @SimpleStacker OP 11 Apr

then i think it'll run forever because number does not iterate

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3 sats \ 0 replies \ @jakoyoh629 11 Apr

lmao. This is an algorithm, it isn't written in any programming language.
I can't code, but Gemini turned my algorithm into Python for me. Ahah

number = 1
found = False

while not found:
found = True

for i in range(1, 21):
if number % i != 0:
found = False
break

if not found:
number += 1

print(f"n = {number}")

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