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nope, no new term was introduced, the negative sign is just taken as common leaving the first term as is
1−(1−1+1−1+…) = 0
Isn't this equation wrong?
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How? Just appearing on the equation at first glance will make that seem wrong if you don't follow the previous steps :) That's not the breaking point
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1−(0) = 0
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let me explain, it was 1 - 1 + 1 - 1 + 1 - 1..... So I kept the first 1, then took the negative sign common for the rest eg 8 - 3 - 5 = 0 or 8 - (3 + 5) = 0 It might look illusionary lol
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My head's spinning! Ahahah